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2.5x^2=5.5x-2.3
We move all terms to the left:
2.5x^2-(5.5x-2.3)=0
We get rid of parentheses
2.5x^2-5.5x+2.3=0
a = 2.5; b = -5.5; c = +2.3;
Δ = b2-4ac
Δ = -5.52-4·2.5·2.3
Δ = 7.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.5)-\sqrt{7.25}}{2*2.5}=\frac{5.5-\sqrt{7.25}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.5)+\sqrt{7.25}}{2*2.5}=\frac{5.5+\sqrt{7.25}}{5} $
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